Question

a wooden block floats in glycerine in such a way that it its 2/5th volume remain above surface if relative density of wood is 0.78 calculate the relative density of glycerine

Answer 1

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Answer 2

On the basis of the laws of flotation,

Weight of the wooden block = weight of the glycerine displaced by immersed part.

Let the volume of block be V

Volume of water displaced = V - 2V/5 = 3V/5 = 0.6V

Density of wood (d) = 0.78 × 1 g/cm³ = 0.78 g/cm³

Density of glycerine = d'

Weight of block = Buoyant force

Vdg = 0.6Vd'g

d' = d / 0.6

d' = 0.78 g/cm³ / 0.6

d' = 1.3 g/cm³

Relative density of glycerine = 1.3 g/cm³ / 1 g/cm³

= 1.3

Thus, the relative density of glycerine is 1.3