A wooden block is placed on the table. it exerts a force of 80 N on the table.if the base area of the block is 2 cm 2 then what will be the measure of the table
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Answer:
Explanation:
Mass of the wooden block, m=5kg
Thrust due to wooden block,
Mg=5kg×9.8ms
−2
=49N
(a) Surface area of 20cm×10cm surface,
A=(20×10)cm
2
=(0.2×0.1)m
2
=0.02m
2
P=
A
mg
P=
0.02m
2
49N
=
0.02
49
Nm
−2
or Pressure, P=2450Nm
−2
.
(b) Surface area of 40cm×20cm surface,
A=(40×20)cm
2
=(0.4×0.2)m
2
=0.08m
2
P=
0.08m
2
49N
=
0.08
49
Nm
−2
or Pressure, P=612.5Nm
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