Question

A Wooden block of 100kg is about to be pushed on a floor of coefficient of friction is 0.4 what is the magnitude of friction on the wooden block when it is just pushed

Answer 1

Normal Force = 100kg * 9.8m/s = 980 or 1000 N
Co-eff = 0.4
Frictional Force, F = Co-eff*Normal Force = 1000*0.4 = 400N

Answer 2

Answer:

The magnitude of friction on the wooden block when it is just pushed is 400N.

Explanation:

The friction is calculated as,

$F=\mu mg$      (1)

Where,

F=frictional force

μ=coefficient of friction

m=mass of the body

g=acceleration due to gravity=10m/s²

As per the question we have,

The mass of the wooden block=100kg

The coefficient of friction=0.4

When the components of equation (1) are substituted, we obtain;

$F=0.4\times 100\times 10$

$F=400N$

So, the magnitude of friction on the wooden block when it is just pushed is 400N.

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