Question

A wooden block of 1kg rests on a smooth surface inclined 30° with horizontal. Find the components
of the weight (of the block) perpendicular and parallel to the plane. (g =9,8 m/s"]
(a) 4.9N, 4.9/3N (b) 4.913N, 4,9N (0)4.9-13 N, SN (d) 4.9N, SN
A
А
B B
с
C
-
D D
Anwar.​

Answer 1

Answer:

Data:

W=mg=1×9.8=9.8N

Q=30°

weight perpendicular = WcosQ = 9.8×Cos(30)= 4.9√3 N

weight parallel= WsinQ= 9.8 × sin(30) = 4.9 N