A wooden block of mass 50 kg and dimensions 10 cm × 30 cm × 50 cm is kept on a table top. The pressure exerted by the wooden block on the table top will be maximum, if it is made to lie on the table on its side of dimension
10 cm × 30 cm
30 cm × 50 cm
10 cm × 50 cm
Either (2) or (3)
Answers
Answer:
- (1) 10cm ×30cm is the required
Given:-
- Mass ,m = 50 kg
- Length of block ,l = 10 cm
- Breadth of block ,b = 30 cm
- Height of block ,h = 50 cm
To Find:-
- Maximum pressure exerted on the top of table
Solution:-
As we have to calculate the maximum pressure exerted by block on the table .
Pressure is defined as the force per unit area.And we also know that, Pressure is inversely proportional to area .
•P ∝ 1/A
where,
- P denote Pressure
- S denote Area
It means that ,
If Area increase then Pressure decreases
If Area decrease then Pressure increases.
So the minimum area on which the pressure applied is maximum .
• A = 10×30 → A = 300 cm²
So the required dimension of the table is 10 × 30
- Option (1) 10×30 is the required answer.
Answer:
10x30 cm
What to find?
➡️We have to find the maximum pressure exerted on the top table.
Lets remember:
If the area increases then the pressure will be decrease..
If the area decrease then the pressure will be increase..
The minimum area on which pressure is apply is minimum..
How to find it?
If we calculate the maximum pressure exerted by wooden block or table then the pressure will be defined as the force of per unit area. Pressure is always inversely proportional with area..
Lets know how answer:
Area=10x30 cm square
=300 cm square
According to your options Hence answer will be 10 cm × 30 cm