A wooden block of mass m1 accelerates at 10ms-2 when a force of 5N acts on it. Another block of mass m2 accelerates at 20ms-2 when same force acts on it. Find the acceleration if both he blocks are tied together and same force acts on their combination.
Answers
Answer:
When a force of 5N gives an acceleration of 10ms-² to a body
then its mass = 5/10 kg = 0.5kg
so, m₁ = 0.5kg
Explanation:
when a force of 5N gives an acceleration of 20ms⁻² to a body
then its mass = 5/20 kg = 0.25kg
so, m₂ = 0.25kg
when the two bodies r tied total mass of the system bcomes = 0.75kg
so acceleration of the system will b = force/mass = 5/0.75 = 6.67 ms⁻²
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Answer:
The answer will be 30 m.
Explanation: Now the things that are given,
acceleration or a = 10 m ;
Force or F = 5N;
and, mass of the =
Now, as we know that,
Force =
Hence, the mass of the is given by,
Mass of body 1 or = Force * Acceleration (i)
Now put the value of the Force and the Acceleration in equation (i);
Mass of body 1 or = 5* 10
= 50 kg
Thus, the mass of body 1 will be 50kg.
Similarly, the mass of body 2 or will be
= 20 * 5
= 100kg
So, we got
= 50kg;
and = 100kg
So, when they tied together then their masses will summed up and resulted mass will be
= 50 + 100 =150;
Here, we have given the force i,e. same force of 5 Newton.
F = 5 N
Now the expression for the acceleration will be given as;
Force = Mass/ Acceleration;
Acceleration = Mass / Force (ii)
Put the values of variable in equation (ii);
Acceleration = 150 / 5
= 30 m.
Therefore, the acceleration of the tied body ,when the force applied is same, will be 30 m.
That's all.