Question

a wooden block of weight 120 N and dimensions 30 CM * 40 CM * 10 CM is kept on a table top. the pressure exerted by wooden block on table top will be ​

Answer 1

1000 Pa

Explanation:

As we know,

P = F/A

here, P is Pressure, F is force and A is Area.

Units :

According to Question, S.I units will be used,

P in Pascal(Pa), F in newton(N) and A in meter² (m²)

Solution :

$\sf = 40 \times 30 \: cm {}^{2} = 12 \times 10 {}^{2} \times 10 {}^{ - 4} \: m {}^{2} \\ \\ \sf \: = 12 \times 10 {}^{ - 2} \: \: m {}^{2}$

F = 120 N

Calculation:

$P \: = \frac{F}{A} \\ \\ = \frac{120}{12 \times {10}^{ - 2} } \\ \\ = 10 \times 10 {}^{2} \\ \\ = 1000 \: Pa$

Therefore, The required pressure is 1000 Pa.