Question

A wooden block starting from rest slides down an inclined plane of length 10 m with an acceleration of 5ms-2. What would be its speed just before reaching the bottom of the plane?

Answer 1

u=0

s=10m

a=5m/s²

t=?

v=?

By s=ut+1/2at²,we get-----

10=0×t+1/2×5×(t)²

10=2/5t²

t²=10×2/5

t²=4

t=2s

Now,by v=u+at----

v=0+5×2

v=10m/s