Question

A wooden block starting from rest slides down an inclined plane of length 10 metre with an acceleration of 5 m/s^2. what would be its speed just before reaching the bottom of the plane?

Answer 1

This can be solved by using 3rd equation of motion
V^2 - u^2 = 2as
Since u=0,
V^2=2as
V^2= 2(5)(10)
V^2=100
V=10
Answer is 10 m/s

Answer 2

Answer:

Here is your answer mate