Question

A wooden block starting from the rest slides down an inclined plane of length 10 m with an acceleration of 5 ms-2. What would be its speed just before reaching the bottom of the plane? plz find this question's answer plz.

Answer 1

Answer:-

Speed of the block just before reaching bottom of the plane is 10 m/s .

Explanation:-

We have :-

• Length of the plane = 10 m

• Acceleration of the block = 5 m/s²

• Initial speed of the block = 0

[As it starts from rest]

To find:-

• Speed of the block just before reaching bottom of the plane.

________________________________

By using the 3rd equation of motion, we get :-

v² - u² = 2as

Where :-

• v is final speed of the body.

• u is initial speed of the body.

• a is acceleration.

• s is distance.

Substituting values, we get :-

⇒ v² - 0 = 2(5)(10)

⇒ v² = 100

⇒ v = √100

⇒ v = 10 m/s

Answer 2

Given :

• The Length of the wooden block is (s) : 10 m
• Acceleration of the wooden block is (a) : 5 m / s ²
• The Initial velocity of wooden block is (u) : 0 m / s [ As , It's starts from rest ]

Exigency To Find : It's speed just before reaching the bottom of the plane ( or final velocity) .

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⠀⠀⠀⠀⠀━━ Now , Finding Final Speed ( or velocity) of the wooden block :⠀

$\dag\:\:\it{ As,\:We\:know\:that\::}$

$\qquad \dag\:\:\bigg\lgroup \sf{ Third \:Equation \:_{(Motion )} \:: v^2 = u^2 + 2as }\bigg\rgroup$

⠀⠀⠀⠀Here v is the final velocity of the body , u is the Initial velocity of the body , a is the Acceleration & s is the Distance Travelled.

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad:\implies \sf v^2 = 0^2 + 2 \times 5 \times 10$

$\qquad:\implies \sf v^2 = 0 + 2 \times 5 \times 10$

$\qquad:\implies \sf v^2 = 2 \times 5 \times 10$

$\qquad:\implies \sf v^2 = 10 \times 10$

$\qquad:\implies \sf v^2 = 100$

$\qquad:\implies \sf v = \sqrt {100}$

$\qquad \longmapsto \frak{\underline{\purple{\:v = 10 m/s\:\: }} }\bigstar$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:Initial \:Velocity \:of\: the \:block \:before \:reaching\: the\: bottom \:of\: the \:plane \:\:is\:\bf{10 \:m / s \:}}}}$

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