Question

A wooden block starting from the rest slides down an inclined plane of length 10 m with an acceleration of 5 ms-2. What would be its speed just before reaching the bottom of the plane? plz find this question's answer plz.​

Answer 1

Answer:

Initial velocity (u) = 0m/s

distance (s) = 10 m

Acceleration (a) = $5 m/s^{2}$

final velocity = ???

$2as = v^{2} - u^{2}$

$2(5) (10) = v^{2} - 0$

$100 = v^{2}$

$v^{2} = 100$

$v = \sqrt{100}$

$v = 10m/s$

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Answer 2

Initial velocity (u) = 0m/s

distance (s) = 10 m

Acceleration (a) = 5m/s²

final velocity = ?

2as=v²-u²

2(5)(10)=v²-0

100=v²

v²=100

v=√100

v=10m/s