Physics, asked by palayesyko, 3 months ago

A wooden block weighing 1.5 N in air is floating in water. A vertical force of 1 N is required to push it
inside the water and submerge it completely.
(i) What is the upthrust experienced by the block when completely immersed in water?
(ii) What is the relative density of the wood?

Answers

Answered by DynamiteAshu
3

Volume of the block immersed in water (v) = 2/3 x net volume (V)

Volume of the block immersed in oil (v) = ¾ x total volume (V)

Let density of wood = ρw g cm-3

Let density of oil = ρo g cm-3

As per the law of floatation;

=

Density of wood

density of water

2

3

=

1000

 Density of wood = 1000 x 2/3 = 667 kg m-3

As per the law of floatation,

=

Density of wood

ensity of oil

3

4

=

667

density of oil

 density of oil = 889.3 kg m-3

Attachments:
Similar questions