A wooden block weighing 200g is attached to a hanger weighing 45g with a fine thread. the block is placed on a frictionless surface and after passing thread over a smooth pulley, hanger is allowed to pull the block. find the acceleration of the system and tension in the string.
Answers
Answered by
2
Answer:
The force pulling the system is .045*9.8 N
That is equal to the acceleration of the system.
a=F/totalmass=.045*9.8/.245 m/s^2
so the tension on the string is the forcepulling on the 200g block...
tension= .200*a=.200*.045*9.8/.245
Answered by
2
Answer:
Hope it helps!!
Explanation:
the force on the system is the weight (m*g) of the hanging mass
... a = f / m
the tension in the string is the force necessary to give the block the calculated acceleration
... t = m a
The force pulling the system is .045*9.8 N
That is equal to the acceleration of the system.
a=F/totalmass=.045*9.8/.245 m/s^2
so the tension on the string is the forcepulling on the 200g block...
tension= .200*a=.200*.045*9.8/.245 Newtons
Similar questions