Physics, asked by ravimajhi244, 8 months ago

A wooden block weighing 200g is attached to a hanger weighing 45g with a fine thread. the block is placed on a frictionless surface and after passing thread over a smooth pulley, hanger is allowed to pull the block. find the acceleration of the system and tension in the string.​

Answers

Answered by aashideshupaliwal852
2

Answer:

The force pulling the system is .045*9.8 N

That is equal to the acceleration of the system.

a=F/totalmass=.045*9.8/.245 m/s^2

so the tension on the string is the forcepulling on the 200g block...

tension= .200*a=.200*.045*9.8/.245

Answered by kavinsiddhu758
2

Answer:

Hope it helps!!

Explanation:

the force on the system is the weight (m*g) of the hanging mass

... a = f / m

the tension in the string is the force necessary to give the block the calculated acceleration

... t = m a

The force pulling the system is .045*9.8 N

That is equal to the acceleration of the system.

a=F/totalmass=.045*9.8/.245 m/s^2

so the tension on the string is the forcepulling on the 200g block...

tension= .200*a=.200*.045*9.8/.245 Newtons

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