Question

A wooden block weighing 200g is attached to a hanger weighing 45g with a fine thread. the block is placed on a frictionless surface and after passing thread over a smooth pulley, hanger is allowed to pull the block. find the acceleration of the system and tension in the string.​

Answer 1

Explanation:

The force pulling the system is .045*9.8 N

That is equal to the acceleration of the system.

a=F/totalmass=.045*9.8/.245 m/s^2

so the tension on the string is the forcepulling on the 200g block...

tension= .200*a=.200*.045*9.8/.245 Newtons

Answer 2

Answer:

The force pulling the system is .045*9.8 N

That is equal to the acceleration of the system.

a=F/total mass=.045*9.8/.245 m/s^2

so the tension on the string is the forcepulling on the 200g block...

tension= .200*a=.200*.045*9.8/.245 Newtons

Explanation:

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