Question

a wooden block weighs 25 N . it is made to stand with its sides dimension 40cm x 20 cm in contact with the surface. calculate the pressure exerted by the wooden block on the surface

Answer 1

Answer:

    P = 3.125 Pascals

Explanation:

Pressure (P) = Force / area

P = 25N / 40 x 20 / 100 m

P = 25 × 100 / 40 × 20

P = 25 / 8

P = 3.125 Pascals

Answer 2

$\huge\purple{ \underline{ \boxed{\mathbb{\red{QUESTION : }}}}}$

A wooden block weighs 25 N . It is made to stand with its sides dimension 40 cm x 20 cm in contact with the surface . Calculate the pressure exerted by the wooden block on the surface .

$\huge\purple{ \underline{ \boxed{\mathbb{\red{ANSWER : }}}}}$

$\red{ \texttt{Pressure exerted by the wooden block on the surface}} \orange = \blue{312.5} \: \tt\red{Pascal}$

$\huge\purple{ \underline{ \boxed{\mathbb{\red{EXPLANATION : }}}}}$

$\green{ \large \underline{ \mathbb{\underline{GIVEN : }}}}$

$\orange{ \texttt{\red{Force} = \blue{25} \red{N}}}$

$\orange{ \texttt{\red{Length of wooden block} \purple{(l)} = \blue{40} \red{cm} = \blue{0.4} \red{m}}}$

$\orange{ \texttt{\red{Breadth of wooden block}\: \purple{(b)} = \blue{20} \red{cm} = \blue{0.2} \red{m}}}$

$\green{ \large \underline{ \mathbb{\underline{TO \: FIND : }}}}$

$\red{ \texttt{Pressure exerted by the wooden block on the surface\ \orange{?}}}$

$\green{ \large \underline{ \mathbb{\underline{FORMULAS \: USED: }}}}$

• $\red{ \tt{Area}} \: \tt \orange{ = \red{l} \times \red{b}}$
• $\orange { \displaystyle\tt{ \red{Pressure} = \frac{\red{Force}}{\red{ Area}} }}$

$\green{ \large \underline{ \mathbb{\underline{SOLUTION: }}}}$

$\orange{ \texttt{\red{Area covered by wooden block} = }} \tt \red{l} \orange{\times} \red{b} \: \: \: \: \: \: \: \: \ \: \\ \\ \orange{ \texttt{\red{Area covered by wooden block} = }} \tt \blue{0.4} \orange{\times} \blue{0.2} \\ \\ \orange{ \texttt{\red{Area covered by wooden block} = }} \tt \blue{0.08} \: \red{m} \: \: \: \: \: \: \:$

$\begin{array}{l}\tiny{\colorbox{purple}{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } }\end{array}$

$\orange { \displaystyle\tt{ \red{Pressure} = \frac{\red{Force}}{\red{ Area}} }} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \orange { \displaystyle\tt{ \red{Pressure} = \frac{ \blue{25}}{ \blue{0.08}} }} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \orange { \displaystyle\tt{ \red{Pressure} = \frac{ \blue{25 \orange{ \times} 100}}{ \blue{8}} }} \: \: \: \: \: \: \: \: \\ \\ \orange { \displaystyle\tt{ \red{Pressure} = \frac{ \blue{2500}}{ \blue{8}} }} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \\ \\ \orange { \displaystyle\tt{ \red{Pressure} = \blue{312.5} \: \red{Pascal}}}$

$\purple{\boxed{\boxed{\red{ \texttt{Pressure exerted by the wooden block on the surface}} \orange = \blue{312.5} \: \tt\red{Pascal}}}}$