Hindi, asked by aditya8687, 1 year ago

a wooden booksheif has external dimension as follows: height=110cm, depth=25cm, breadth=85cm. the thickness f the plank is 5cm everywhere. the external faces are to be polished and the inner faces are to be painted. if the rate of polishing is 20 paise per sq cm and the rate of paintingis 10 paise per sq cm, find the total expenses required for polishing and painting the surface of the booksheif.

Answers

Answered by Raziulla
1

1 + 2 + 1 + 2 + 3 + 4 + 5 + 6 + 10 + 25 into 45 is equal to 10 2044

Answered by ItzMissKomal
0

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External length (l) of bookshelf=85㎝

External breadth (b) of bookshelf=25㎝

External height (h) of bookshelf=110㎝

External surface area of book shelf while leaving out the front face of the shelf=lh+2(lb+bh)

=(85×110)+2(85×25+25×110)

=9350+9750

=19100㎠

Area if front face=(85×110)−75×100+2(75×5)

=1850+760=2600㎠

Area to be polished=19100+2600=21700㎠

Cost of polishing=Rs. 21700×0.20=Rs.4340

Length, breadth and height of each row of bookshelf are

75㎝,20㎝ & 30㎝ respectively. From the figure Area to be painted in 1 row=2(l+h)b+lh

=2(75+30)20+75×30

=6450㎠

Area to be painted in 3 rows=3×6450=19350㎠

Total cost of painting=Rs.(19350×0.1)=Rs. 1935

Total expenses=Rs.

(4340+1935)=Rs. 6275(4340+1935)=Rs.6275

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