Question

A wooden box of weight 14kgf of area of cross section 5 m2 is kept on a table. Calculate the pressure exerted by the box in si unit.​

Answer 1

Explanation:

Solution :

Here Mass of wooden block m= 4kg <br> Acceleration dur to gravity ,

<br> Weight of wooden block

<br>

<br> =40 N <br> since weight is a force,so we can say that the force excerted by the wooden block on the table top is 40 N .We will now calculate the pressure in the two cases. <br> width="80%"> <br> (a) In the first case : Force = 40 N (Calculated above) <br>

<br>

<br> Now Pressure

(or 320) <br> Thus the pressure exerted by the wooden block on table top when kept on its face measuring

is 320

of 320 pascals (see Figure 44) <br> (b) In the second case : Force = 40 N (Same as above) <br> Area

<br>

<br>

(or 1600) <br> Thus the pressure exerted by the wooden block on table top when kept on its face measuring

is 1600 N

Answer 2

Answer:

2.8 Pa

Explanation:

Weight = Force exerted = 14 kgf = 14 N

Cross-sectional area = 5 m^2

So, Presseure exerted = Force / Area = 14/5 = 2.8 Nm/s^2 = 2.8 Pa (Pascal)