Question

a wooden box who's value is 1300₹ is fine wood cost is 25₹/m . length of the box is 4m and breath is 3m find its height
​

Answer 1

❏ Correct Question:-

@ A wooden box who's value is 1300₹ is fine wood cost is 25₹/m² . length of the box is 4m and breath is 3m find its height

❏ Solution:-

$\setlength{\unitlength}{0.74 cm}\begin{picture}(12,4)\thicklines\put(5.6,5.6){ A }\put(11.1,5.8){ B }\put(11.08,8.9){ C }\put(5.46,8.7){ D }\put(3.55,10.15){ E }\put(3.55,7.15){ F }\put(9.14,10.235){ H }\put(9.14,7.3){ G }\put(3.3,6.3){ 3\:m }\put(7.75,6.2){ 4\:m }\put(11.1,7.5){ h\:m }\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\put(4,7.3){\line(1,0){5}}\put(4,10.3){\line(1,0){5}}\put(9,10.3){\line(0,-1){3}}\put(4,7.3){\line(0,1){3}}\put(6,6){\line(-3,2){2}}\put(6,9){\line(-3,2){2}}\put(11,9){\line(-3,2){2}}\put(11,6){\line(-3,2){2}}\end{picture}$

Now , according to the question The wooden box is cost 1300 Rs at 25 Rs/m².

Therefore, Total Surface area of the wooden box is , = $\dfrac{1300}{25}\:Rs$ = 52 m².

Now, we know that total surface area of a cuboid is ,

$\sf\implies T.S.A.=2(lb+bh+hl)$

where,

T.S.A.=Total Surface area .

l = length,

b= breadth,

h = height,

Hence,

$\sf\implies 52=2(4\times3+3\times h+h\times4)$

$\sf\implies \dfrac{\cancel{52}}{\cancel2}=12+3 h+4h$

$\sf\implies 26-12=3 h+4h$

$\sf\implies 14=7h$

$\sf\implies \dfrac{\cancel{14}}{\cancel7}=h$

$\sf\implies \boxed{\large{\red{h=2\:m}}}$

Hence , Height of the Wooden Box was 2 metre.

Answer 2

$\huge\underline\mathrm{SOLUTION:-}$

AnswEr:

• The height of a wooden box = 2 m.

Given:

• A wooden box who's value is 1300₹ is fine wood cost is 25₹/m .
• Length of the wooden box is 4m.
• Breath of wooden the box is 3m.

Need To Find:

• Find the height of a wooden box = ?

ExPlanation:

$\setlength{\unitlength}{0.74 cm}\begin{picture}(12,4)\thicklines\put(5.6,5.6){ A }\put(11.1,5.8){ B }\put(11.08,8.9){ C }\put(5.46,8.7){ D }\put(3.55,10.15){ E }\put(3.55,7.15){ F }\put(9.14,10.235){ H }\put(9.14,7.3){ G }\put(3.3,6.3){ 3\:m }\put(7.75,6.2){ 4\:m }\put(11.1,7.5){ h\:m }\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\put(4,7.3){\line(1,0){5}}\put(4,10.3){\line(1,0){5}}\put(9,10.3){\line(0,-1){3}}\put(4,7.3){\line(0,1){3}}\put(6,6){\line(-3,2){2}}\put(6,9){\line(-3,2){2}}\put(11,9){\line(-3,2){2}}\put(11,6){\line(-3,2){2}}\end{picture}$

According to the given question:

• A wooden box is cost Rs. 1,300 at 25 RS/m². [Given]

Hence:

• T.S.A of wooden box = 1300/25 RS = 52m².

Now, Formula used here:

• T.S.A = 2(lb + bh + hl)

Putting the values according to the given formula:

➠ 52 = 2(4 × 3 + 3 × h + h × 4

➠ 52/4 = 12 + 3h + 4h

➠ 26 - 12 = 3h + 4h

➠ 14/7 = h

➠ ${\underline{\boxed{\sf{Height = 2}}}}$

ThereFore:

• The Height of a wooden box = 2 metre.

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$

Additional Information:

Here,

• L is used for Length.
• B is used for Breadth.
• H is used for Height.
• T.S.A = 2(lb + bh + hl)
• T.S.A is used for Total surface of area.

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$