A wooden cube having mass 10 kg is dropped from the top of a building . After 1 s , a bullet of mass 20 g fired at it from the ground hits the block with a velocity of 1000 m/s at an angle of 30o to the horizontal moving upwards and gets imbedded in the block . The velocity of the block/bullet system immediately after the collision is: 17 m/s 27 m/s 52 m/s 10 m/s
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Answer:
Correct option is
B
40ms
−1
upward
Time after which collision takes place
t=
u
h
=
100
100
=1sec
Initial velocity of the wooden block
u
1
=gt=10×1=10m/s
Initial velocity of the bullet
u
2
=u−gt=100−10×1=90m/s
m
1
u
1
−m
2
u
2
=(m
1
+m
2
)V
∴V=−40m/s
Hence the velocity immediately after collision will equal to 40 m/s in the upward direction .
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