A wooden cube of a side a is placed on a horizontal surface and the coefficient of static friction between them u.Another cube of same wood but length 2a is placed on same surface.then the coefficient of static friction is
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Answer:
m=ρ×v
m
1
=ρ(a)
3
and m
2
=ρ(2a)
3
=8ρa
3
⇒m
2
=8m
1
⇒ normal reaction increased by 8 times
therefore, friction force also increses by 8 times.
And, as the block is moving with constant velocity, thus a=0
thus, F= friction force
∴ F increases by 8 times.
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