Question

A wooden cube of a side a is placed on a horizontal surface and the coefficient
of static friction between them pi . Another cube of same wood but length 2a is
placed on the same surface. Then the coefficient of static friction is​

Answer 1

Answer:

m=ρ×v

m

1

=ρ(a)

3

and m

2

=ρ(2a)

3

=8ρa

3

⇒m

2

=8m

1

⇒ normal reaction increased by 8 times

therefore, friction force also increses by 8 times.

And, as the block is moving with constant velocity, thus a=0

thus, F= friction force

∴ F increases by 8 times.

Explanation:

i hope this helps you a lot

Answer 2

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