A wooden cube of side 10 cm has mass 700 g. What part of it remains above the water surface while floating vertically on the water surface?
Ans 3 cm in height
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Answer:
We know that the volume of part submerged in a liquid is given by, V=
Density of liquid
Density of body
Density of cube =
Volume
Mass
=
10
3
700g
=0.7g/cm
3
So, density of water =1g/cm
3
So, part of cube submerged in water =
Density of water
Density of body
=0.7/1=7/10
∴ Part of cube above water =1−7/10=3/10
i.e. 3cm of cube is above water.
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