Question

A wooden cube of side 10cm has mass 700g which part of it remains above the water surface while floating vertically on the water surface?

Answer 1

Vc = (10cm)^3 = 1000 cm^3.=Vol. of cube

Dc = 700g / 1000cm^3 = 0.7 g/cm^3. =

Density of cube.

ha = h-(Dc/Dw)*hc,

ha = 10 - (0.7/1)10 = 3 cm. = Ht. above

water.

hope it helps you dear

Answer 2

Answer:

The floating is 30%.

Explanation:

Given that,

Side of cube = 10 cm

Mass of cube= 700 g

We need to calculate the density

Using formula of density

$\rho=\dfrac{m}{V}$

Put the value into the formula

$\rho=\dfrac{700}{10^3}$

$\rho=0.7\ g/cm^3$

We need to calculate the floating vertically on the water surface

Using formula of floating

$F=1-\dfrac{\rho_{c}}{\rho_{w}}$

Put the valu into the formula

$F=1-\dfrac{7}{10}$

$F=0.3\times100$

$F=30\%$

Hence, The floating is 30%.