A wooden cuboid has a mass of 8 kg the Length breadth and height is100, 50 and 20. Find the pressure on the floor on which the block is kept.
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Answered by
9
Mass = 8kg
Area of surface on which cuboid is placed = lb = 100 × 50 sq. units
Pressure = F/Area
F= ma = 8 × 10 = 80N
Here a=g=10m/s^2
Pressure=80N/5000sq. units = 400000 N/sq.unit
Hope it helps
dhanush3007:
thanks a lot
Answered by
3
M = 8kg
L = 100
B = 50
H = 20
We know P = F / A
F = M * g
= 8 * 10 = 80 N
Area of cuboid = 2(LB + BH + HL)
= 2(100*50 + 50*20 + 20*100)
= 2(5000 + 1000 + 2000)
= 2 * 8000
= 16000 m^2
Now put values in formula
P = 80 / 16000
= 0.002 N / m^2
Thanks
L = 100
B = 50
H = 20
We know P = F / A
F = M * g
= 8 * 10 = 80 N
Area of cuboid = 2(LB + BH + HL)
= 2(100*50 + 50*20 + 20*100)
= 2(5000 + 1000 + 2000)
= 2 * 8000
= 16000 m^2
Now put values in formula
P = 80 / 16000
= 0.002 N / m^2
Thanks
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