Question

A wooden cuboid has mass of 8 kg. The length, breadth and height of this wooden cuboid are 100 cm, 50 cm and 20 cm, respectively. Find the pressure on the floors on which this block is kept.

Answer 1

pressure =Force or Thurst/Area
Area=L×B = 100cm =1m
50cm=0.5 m
1×0.5
=0.5m²
force=m×a
m=8kg
a=10m/s (a is acceleration due to gravity [g])
8×10=80N
pressure=F/A
=80/0.5 Pa
=160Pa (Pascal is SI unit of pressure denoted Pa)
if this help you mark this as brainliest thanks.
and this belongs to physics not chemistry

Answer 2

Answer:

Explanation:

Weight of the block=8x10=80N

Pressure when block placed on side 100 cm and 50 cm

P=F/A=80/(1x0.5)=160 Pa

Pressure when block is placed on side 50 cm and 20 cm

P=F/A=80/(0.5x0.2)=800 Pa

Pressure when block is placed on side 20 cm and 100 cm

P=F/A=80/(0.2x1)=400Pa

Hope it helps you.