Question

a wooden piece 5 N in weight and 5cm×3cm×2cm in size lies on 5cm×2cm face. what is the pressure exerted by it in Newton cm square? solve step by step please.

Answer 1

Hey, there!

Here's the answer you are looking for.

Pressure = Force per unit area

Mathematically,

P = F/A

Here, F = weight of the wooden block = 5N

and

A = area of the face on which it lies = 5×2 cm² = 10cm²

So, pressure (in Newton/cm²)

= (5/10)N/cm² = 0.5N/cm²

Hope that helps.

Thanks.

Answer 2

The pressure exerted by the box on the surface is $0.5\ N/cm^2$.

Explanation:

Given that,

Weight of the wooden piece, W = 5 N

Dimension of the box is 5 cm×3 cm×2 cm. It lines on 5 cm×2 cm face. We need to find the pressure exerted by it. We know that the the net force per unit area is called pressure exerted on that face. It is given by :

$P=\dfrac{F}{A}$

$A=10\ cm^2$

$P=\dfrac{5\ N}{5\ cm\times 2\ cm}$

$P=\dfrac{5\ N}{10\ cm^2}$

$P = 0.5\ N/cm^2$

So, the pressure exerted by the box on the surface is $0.5\ N/cm^2$. Hence, this is the required solution.

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