Question

A wooden raft of density 600kg/m cube and mass 120 kg floats in water how much weight in kg can be put on it to make its volume sink and top surface coincide with the water surface

Answer 1

hey friend there is answer !!!!!

I hope you help !!!!
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Okay!

Assuming density of water to be 1000 kg/m3

we have

Total mass of object+mass of body 2=weight displaced in water

Total mass of object= 120kg=120X9.81N

Mass of body 2= let it be m

Weight displaced in water=1000X(volume of object) X9. 81

Volume of object= mass/density=120/600=0.2 m3

Hence

m+1177.2=1962

Or m=784.8N=784.8/9.81=80kg

Answer 2

Heyaa...☺️

HERE IS UR ANSWER :-

Assuming the density of water to be 1000 kg/m3

We have,
Total mass of object + mass of body 2 = weight displaced in water

Total mass of object = 120 kg = 120X9.81N

Let mass of body 2 be m

Weight displaced in water = 1000 × (vol. of obj.) × 9.81

Volume of object = Mass/Density = 120/600 = 0.2 m3

HENCE,
m + 1177.2 = 1962

OR m = 784.8N = 784.8/9.81 = 80 kg