Math, asked by ramji69singh, 3 months ago

a wooden solid cylinder has a radius 4 cm and height 7 cm . to increase its weight a conical hole is drilled in the cylinder and is completelly filled with a metal. the conical hole has a radius 3/2 cm and height is 3 cm . calculate the ratio of the volume of the wood to the volume of the metal in the solid

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Answered by mehakshakya34
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A metallic cylinder has radius 3cm and height 5cm. It is made of metal A. To reduce its weight, a conical hole is drilled in the cylinder, as shown and it is completely filled with a lighter metal B. The conical hole has a radius of 3/2cm and its depth is 8/9cm. Calculate the ratio of the volume of the metal A to the volume of the metal B in the solid.

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Volume of metal B=

3

1

πr

1

2

h

1

=

3

1

π(

2

3

)

2

(

9

8

)=

3

Volume of metal A=πr

2

h−

3

1

πr

1

2

h

1

=

3

π

(3r

2

h−r

1

2

h

1

)

=

7×3

22

(3×9×5−

4

9

×89)=

21

22

(135−2)=

21

22×133

=139.33 cm

3

ratio =

139.33×3

=

3.14

209

=

π

209

=

22

209×7

=

2

133

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