Physics, asked by gogogogo8365, 9 months ago

A wooden tie bar is 75 mm wide, 150 mm deep and 1.50 m long. It is subjected to an
axial pull of 45000 N. The stretch of the member is found to be 0.6380 mm. Find the
young’s modulus for the material.

Answers

Answered by skumarsanthosh23
1

Answer:

Elastic moduli characterization of wood using the Impulse Excitation Technique . ... 3.3.2 Shear modulus (modulus of rigidity) . ... It has a span of 44 m, height of 33 m and width of 4.8 m [3] .

Answered by m8335940
0

Answer:

9405 Mpa

Explanation:

E=45*10^3*150/(75*150)*0.638

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