Physics, asked by satyakumar07770, 1 month ago

A wooden wheel of 2000 mm diameter is to be fitted with a steel ring of 1990 mm internaldiameter. Determine (a) Stress developed in steel and (b) Minimum temperature required to fitthe steel ring over wooden wheel. Take Young's modulus of steel as 2 x 105 N/mm2 and Coefficient of thermal expansion as 12 x 10-6/0C​

Answers

Answered by Pankajsutariya
1

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Answered by shilpa85475
0

A wooden wheel of 2000 mm diameter is to be fitted with a steel ring of 1990 mm internal diameter  is :

Stress developed in steel :

  • The effect of wind or seismic load is taken in to account,then the permissible stress in steel are increased by 33⅓ percent.
  • Some are rivets, bolts and tension rods, the permissible stresses are increased by 25 per cent, when the effect of wind or seismic load is taken in to account is reffered as a stree developed in steel.

Minimum temperature required to fitthe steel ring over wooden wheel :

  • The minimum temperature in winter is 0 0 F and the maximum temperature is 10  F .
  • The tower is made of steel.
  • The coefficient of linear expansion of steel is 12 × 10 −6 / 0C .
  • Modulus of rigidity, bulk modulus and change in volume if Poisson’s ratio = 0.3 and Young’s modulus E = 2 ×105 N/mm2.
  • A circular rod of diameter 20 mm and 500 mm long is subjected to a tensile force 50kN.
  • The modulus of elasticity for steel may be taken as 200 kN/mm2.
  • A 2000 mm long steel tube of 1990 mm internal diameter and 15 mm thick is surrounded closely by brass tube of same length and thickness.
  • The tube carries an axial thrust of 100 kN .
  • Estimate load v carried by each tube and amount of sharing of each tube.
  • Es = 200 x 103 N/ mm2 and Eb = 100x 103 N.
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