A work can be done by 10 men and 15 women in 6 days. The same work can be done by 12 men and 27 women in 4 days. How many days will it take for 6 men and 11 women to complete the same work?
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Correct option is D)
1 man can finish the whole work in 100 days
∴ 1 man's 1 days' work =1001
⇒ 10 men's 1 days' work =10×1001=101
Let the time taken by one woman to finish the work be x days.
Then, 1 woman's 1 days' work =x1
⇒ 15 women's 1 days' work =x15
Given, (10 men's + 15 women's ) 1 days' work =61
⇒101+x15=61⇒x15=61−101=305−3=302=151
⇒x=225 days.
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