Math, asked by subhas6045, 10 months ago

a work for 12 days,b for 15 days together for 6 days, remaining work how much​

Answers

Answered by jinadevkv
0

Answer:

2/5 part of the work is remaining

Step-by-step explanation:

Take LCM of 12 and 15 = 60

Let total work = 60

a does 60/12 = 5 works a day

b does 60/15 = 4 works a day

In 6 days together they do (5+4)*6 = 9*6 = 36 works

Remaining work = 60-36 = 24 parts = 24/60 = 2/5

Answered by stark1436ark
0

Work done by A in one day is 1/12

Work done by B in one day is 1/15 so,

Work done by (A+B) in one day is 1/12+1/15=9/60

So work done by A+B in 6 days is 9/60×6= 54/60 so remaining work is 1-54/60= 6/60= 1/10

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