a work for 12 days,b for 15 days together for 6 days, remaining work how much
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Answer:
2/5 part of the work is remaining
Step-by-step explanation:
Take LCM of 12 and 15 = 60
Let total work = 60
a does 60/12 = 5 works a day
b does 60/15 = 4 works a day
In 6 days together they do (5+4)*6 = 9*6 = 36 works
Remaining work = 60-36 = 24 parts = 24/60 = 2/5
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Work done by A in one day is 1/12
Work done by B in one day is 1/15 so,
Work done by (A+B) in one day is 1/12+1/15=9/60
So work done by A+B in 6 days is 9/60×6= 54/60 so remaining work is 1-54/60= 6/60= 1/10
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