a work force of 630 men can complete a piece of work in 15 days after 4 days 140 more men were hired how long willis take to complete the work now
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men days portion of work
630 15 1 (whole)
630 1 1/15
1 1 1/15 x 630
Now ,
for 4 days 630 men have been doing work.
portion of work completed = 4 x 1/ 15 = 4/15
work left to be done = 1 - 4/15 = 11/15
no of additional men = 140
total men working = 140 + 630 = 770
men days portion of work
1 1 1/ 15 x 630
770 1 770 / 15 x 630
770 d 770 d / 15 x 630
Now 770 d / 15 x 60 = 11 /15
d = 6/7 days
Hope my answer is correct.
630 15 1 (whole)
630 1 1/15
1 1 1/15 x 630
Now ,
for 4 days 630 men have been doing work.
portion of work completed = 4 x 1/ 15 = 4/15
work left to be done = 1 - 4/15 = 11/15
no of additional men = 140
total men working = 140 + 630 = 770
men days portion of work
1 1 1/ 15 x 630
770 1 770 / 15 x 630
770 d 770 d / 15 x 630
Now 770 d / 15 x 60 = 11 /15
d = 6/7 days
Hope my answer is correct.
santy21:
ans is 9 days
OK I'll recheck my answer.
d= 63/7 = 9 days..........Just calculation mistake, you see the approach.
It should be 630 instead of 60.
in the last step.
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