Math, asked by choubeyradha, 7 months ago

A work is assigned to 6 men and 12 women, and they could complete it in 3 days. It was alo denied to
together they can do 7 times as much work a man and a woman can do. In how many drys wall
have done the work?

Answers

Answered by jasmeetsingh29
0

Answer:

o, one man can complete x amount of work alone in 108 days. Total work done = Remaining work = x - = 6 Men + 12 .

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