A work is being completed by a group of 10 men in 12 days. Same work
is completed by a group of 10 women in 6 days. In how many days will
the work be completed if both the groups work together?
(a) 4
(b) 6
(c) 9
(d) 18
Answers
Gɪᴠᴇɴ :-
- 10 Men complete a work in = 12 Days.
- 10 women complete same work in = 6 Days.
Tᴏ Fɪɴᴅ :-
- In how many days will the work be completed if both the groups work together?
Sᴏʟᴜᴛɪᴏɴ :-
Since work is same in Both case we can say That,
→ 10M * 12 = 10W * 6
→ 2M = 1W
So,
→ 2M = 1W
→ 10M = 5W .
Therefore,
→ Whole Group = 10M + 10W = 5W + 10W = 15W.
Now,
→ 10 women can complete work in = 6 Days.
→ 1 women will complete same work in = (6 * 10) Days.
→ 15 women will complete same work in = (6*10)/15 = 4 Days. (Ans.)
Hence, Both the groups working together complete the same work in 4 Days.
Given :
- 10 men's one day's work = 12 days
- 10 women's one day's work = 6 day's
To find :
- The work be completed if both the groups work together = ?
Step-by-step explanation :
According to the question :
10 men's one day's work = 1/12
∴ 1 man one day's work = 1/12
= 1/12 × 10
= 1/120
Similarly,
1 woman one day's work = 1/6 × 10
= 1/60
∴ ( 1 man + 1 woman) 's one days,
= 1/120 + 1/60
= 1 + 2/120
= 3/120
= 1/40
∴ ( 10 man + 10 woman) 's are day's work
= 10/40
= 1/4
Therefore, both the team can finish the whole work in 4 days .
Hence,
Option (a). 4 days is the correct option ✔️