Question

A work is done by three people A, B and C. A alone takes 20 hours to complete a single product but B and C working together takes 8 hours, for the completion of the same product. If all of them worked together and completed 28 products, then how many hours have they worked?​

Answer 1

Answer:

hii

your answer is here !

Step-by-step explanation:

=>1/A = 1/20 and

=>1/B + 1/C = 1/8 (Given)

=>1/A + 1/B + 1/C = 1/8 + 1/20 = 7/40

=>In 40 hours, working together they will complete 7 products.

=> Thus in 160 hours they will complete 28 products

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Answer 2

Answer:

Step-by-step explanation:

Aloha !

Given,

1/A=1/20

1/B+1/C=1/8

Now,

1/A+1/B+1/C=1/20+1/8

=2+5/40

=7/40

For 7 hours they will be do 40 products.For 28 hours they will do 160 products.

Thank you

@ Twilight Astro ✌️☺️♥️