A work of 16000 joules is done on a load of mass of 60 kg to lift a certain height calculate the height through which it is lifted (g=9.8 m/s^2)
Answers
Answered by
5
Answer:
Work,W=mgh
h=
mg
W
=
20×9.8
784
=4m
Answered by
7
Given :
Work done = 16000J
Mass of the object = 60 kg
Gravitational field = 9.8 m/s²
To find :
The height through which it is lifted.
Solution :
Potential energy is energy due to position.
- Potential energy is scalar quantity having magnitude.
- Sl unit of P.E is Joules.
- CGS unit of P.E is erg.
Potential energy of an object is given by
P.E = mgh
where,
- P.E denotes potential energy.
- m denotes mass.
- g denotes gravitational field.
- h denotes height.
Substituting all the given values in the formula,
➠ P.E = mgh
➠ 16000 = (60)(9.8)(h)
➠ 16000 = 588h
➠ h = 16000/588
➠ h = 27.21m
thus, the height through which it is lifted is 27.21 m.
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