Question

A work of 4900j is done on road of mass 50 kg to lift it to a certain height. Calculate the height through which the load is lifted. ​

Answer 1

Given :

• Work Done (W) = 4900 J
• Mass of load (m) = 50 kg

To Find :

• Height Through which the load is lifted

Solution :

We are given work done in lifting a load, mass of load is also given, we can find this question by using Work Energy Theorem.

$\underbrace{\sf{Height \: through \: which \: load \: is \: lifted}}$

As we know that, by work energy theorem :

$\implies \sf{W \: = \: P.E} \\ \\ \implies \sf{W \: = \: mgh} \\ \\ \implies \sf{4900 \: = \: 50 \: \times \: 9.8 \: \times \: h} \\ \\ \implies \sf{4900 \: = \: 490h} \\ \\ \implies \sf{h \: = \: \dfrac{4900}{490}} \\ \\ \implies \sf{h \: = \: 10}$

$\therefore$ Height through which load is lifted is 10 m

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Same type of question answered by me :

https://brainly.in/question/17754486

Answer 2

★ Given :

Work Done (W) = 4900 J

Mass of load (m) = 50 kg

$\rule{150}{2}$

★ To Find :

We have to find the height through which the load is lifted.

$\rule{150}{2}$

★ Solution :

We know the formula to calculate work done.

$\Large{\implies{\boxed{\boxed{\sf{Work = mgh}}}}}$

★ Putting Values ★

$\sf{\dashrightarrow 4900 = 50 \times 9.8 \times h} \\ \\ \sf{\dashrightarrow h = \frac{4900}{50 \times 9.8}} \\ \\ \sf{\dashrightarrow h = \frac{\cancel{4900}}{\cancel{490}}} \\ \\ \sf{\dashrightarrow h = 10} \\ \\ \Large{\implies{\boxed{\boxed{\sf{h = 10 \: m}}}}}$