Question

a work twice as fast as B and C work thrice as fast as a if all of them work simultaneously they complete the work in 18 days find the time taken by C alone to complete the work​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

From Given facts

If X is the work done by B, then work done by A is 2X

Irrespective of duration Total work is X+2X = 3X

ie B did 1/3 of work in 24 days and A did 2/3 of work in 24 days

since B finished only 1/3 work in 24 days , to complete the full work by him alone is 24/ 1/3 = 24* 3= 72 days