Question

a workman cut of 1/5 th of a pipe. the piece he cut off, was 3 meters long. what was the length of original pipe? ​

Answer 1

Given :- A workman cut of 1/5 th of a pipe. the piece he cut off, was 3 meters long. what was the length of original pipe ?

Solution :-

Let us assume that, the length of original pipe is x m .

Than,

given that, workman cut of (1/5)th of pipe , and the piece he cut off was 3 m long.

So, we can say that,

→ (1/5) of original length = 3m

→ (1/5) of x = 3 m.

→ (1/5) * x = 3 m.

→ x = 5 * 3

→ x = 15m (Ans.)

Hence, Length of original Pipe was 15m.

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Answer 2

SOLUTION :

GIVEN

• A workman cut of 1/5 th of a pipe

• He cut off, was 3 meters long

TO DETERMINE

The length of original pipe

EVALUATION

SOLVE USING RULES OF THREE

$\sf{}Part \: of \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: Length \: of$

$\sf{}the \: pipe \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: the \: pipe (metre)$

$\displaystyle \sf{} \:\: \: \frac{1}{5} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 3$

$\displaystyle \sf{} \:\: \: 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ?$

Now from above we observe that as part of pipe increases then the length of the pipe will also increase

So Part of the pipe and length of the pipe are in continued proportion

So the full length of the pipe

$\displaystyle \sf{} = 3 \times \frac{1}{ \frac{1}{5} }$

$\displaystyle \sf{} = 3 \times 5$

$\displaystyle \sf{} = 15$

FINAL RESULT

The length of original pipe is 15 metre

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