A workman is paid ₹150 for each day he works and is fined ₹50 for each day he is absent. In a month of 30 days he earned ₹2100. For how many days he remain absent ?
Answers
Answered by
1
9 days
150-50= 100. (1)
therefore he gets rs100 per day
therfore 30 days=3000
3000-2100=900
therefore x×100=900
=9 days
Answered by
20
let the days he was absent be x
he was worked ( 30 - n )
total wage = 2100 = 150 × ( 30 -n ) - 50x
4500 - 200x = 2100
4500 - 200x = 2100
200x = 4500 - 2100
200x = 2400
x = 2400 ÷ 200
x= 12 days he was absent , hence proved
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