A works 3times faster than B and A can finish the work 60days before B then how long it will take to complete the work if they did it together?
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Step-by-step explanation:
atq,
work done by a =60 days
work done by b = 3×60 =180 dayd
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0
Answer:
Let the total work be W. Then, Speed of B=60W and Speed of A = 603W. So, Time taken (in days) when they work together. =60W+603WW. =15 days. Thus, correct ...
Explanation:
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