Question

A works half of B's ​​3/4 of the time. If A and B work together in 18 days, then B alone will work in how many days?​

Answer 1

Step-by-step explanation:

Time A works

$\frac{1}{2} \times \frac{3}{4} = \frac{3}{8} of \: time \: taken \: by \: b$

WORK DONE BY A IN 1 DAY IS

$\frac{3}{8} \: OF B'S$

WORK DONE BY A+B IN 1 DAY IS

$\frac{1}{18}$

Work done by A in 1 DAY is

$\frac{3}{8} of \: b$

Work done by B in 1 day is

$\frac{3}{8} - \frac{1}{18} = \frac{23}{72}$

which is

$\frac{72}{23}$

Answer

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