Question

A works twice as fast as B. If B can complete
a piece of works independently in 12 days, then
the number of days taken by A and B toget
together to finish the work.​

Answer 1

Answer:

A and B together can finish the work in 4 days.

Step-by-step explanation:

Ratio of rates of working of A and B = 2 : 1.

So, ratio of times taken = 1 : 2

B's 1 day's work = 1/12

∴A's one day's work= 1/6 (2 times the work of B)

(A+B)'s one day's work= 1/6+ 1/12 = 1/4

Therefore, A and B together can finish the work in 4 days.

Answer 2

Question understanding :-

• Here, It is mentioned in the question that there are two people one is denoted by A and Other is denoted by B .

• Now, It is mentioned that A is working twice faster than B

• Here, It is also mentioned that B complete his work in 12 days

Now, We have to find that in how many days they both complete the work if they work together ?

Given :-

• A work twice as fast as B

• B can complete a piece of work independently in 12 days

Solution :-

Here, A is twice faster than B

The ratio of rates of working A and B

= 2 : 1

So ,

Time ratio of B = 1/12

Therefore,

Time ratio of A will be = 2/12 = 1 / 6

Here,

We find that if B will finish his work in 12 days so A will finish it in 6 days

According to the question,

If ( A + B) working together .

Then,

(A + B ) ratio of rates of working

= 1 / 6 + 1/ 12

= 2+ 1/12

= 3/12

= 4

Hence, A and B both finish there work in 4 days $.$