Question

A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in :

Answer 1

I THINK ITS 3 DAYS BECAUSE :B=12 DAYS
                                                     A=6*2=12=6 DAYS
A AND B TOGETHER                  A+B= 6-3=3 DAYS..

THIS IS MY CALCULATION IF ITS CORRECT PLZ MARK THIS ANSWER AS THE BEST !!!

Answer 2

B's 1 days work = 1/12. So, A's 1 days work = 1/6 (A+B)'s 1 day's work = 1/12 + 1/6 = 1/4. So, both together can finish the work in 4 days. Plz remarks give remarks my answer.