a works twice as fast as B if both of them can do together finish a piece of work in 12 hours then hw many time will B take to do it
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A work = 2×B work
Let work done by B is b hours
B one day work = 1/b
then A one day work = 2/b
A+B can do the work in 12 hours
so A+B one day work =1/12
1/b+ 2/b =1/12
3/b =1/12
1/b= 1/36
2/b = 1/18
B takes 36 hrs
A takes 18 hrs
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