Question

A works two times faster than B. If B can complete a piece of work independently in 10 days find how many days will A and B together take to complete the work.​

Answer 1

Answer:

A and B together will take $\frac{10}{3}$ days to complete the work.

Step-by-step explanation:

Let there is '30' pieces of work,

From the given situation that 'A works two time faster than B',

Work done by A in one day = 2 x (Work done by B in one day)

Since B takes 10 days to complete the work,

Pieces of Work done by B in one day = $\frac{30}{10} = 3$

Hence, Piece of Work done by A in one day = 2 x 3 = 6

Thus, Piece of Work done by A and B together in one day = 6 + 3 = 9

Hence, to complete the work together A and B will take, $\frac{30}{9}=\frac{10}{3}$ days