A wrench is used to tighten a nut. A 15N perpendicular force is applied 50cm away from the axis of rotation, and moves a distance of 10 cm as it turns. What is the torque applied to the wrench?
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Answer:
iven = force (F) = 15N
distance (d) = 10cm
to find :-
torque = ?
solution,
torque = d × F
convert the values in the simple form /unit.
10cm = 0.10m
50cm= 0.50m
torque = F × d
= 15 × 0.10 × 0.5
= 7.5Nm
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