Math, asked by honeybee48, 7 months ago

a. Write 30685 correct to 3 significant figures
b. Write 0.050462 correct to 3 significant figures

Answers

Answered by rashich1219
2

Given:

(a)- 30685 and (b)- 0.050462

To Find:

a. Write 30685 correct to 3 significant figures .

b. Write 0.050462 correct to 3 significant figures.

Solution:

To determine the significant figure of a number , 3 points we have to keep in mind;

  • Non-zero digit is always significant.
  • Any zero between non-zero (significant) digit is significant.
  • A final zero in the decimal portion only are significant.

(a)- 30625;

It has 5 significant figure. To correct it to 3 significant figures

we have ,

\[\begin{gathered}   \Rightarrow 30685 \hfill \\   = 3.0685 \times {10^4} \hfill \\   = 3.07 \times {10^4} \hfill \\ \end{gathered} \]

Hence, 3.07 × 10^{4} have 3 significant figures.

(b)- 0.050462

It has  5 significant figures . To correct it to 3 significant figures

we have,

\[\begin{gathered}   \Rightarrow 0.050462 \hfill \\   = 5.0462 \times {10^{ - 2}} \hfill \\   = 5.05 \times {10^{ - 2}} \hfill \\ \end{gathered} \]

Hence, 5.05 × 10^{-2} have 3 significant figures.

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