Question

(a) Write a chemical equation for the preparation of SO2 industrially.
(b) What happens when SO2 is passed through water.
(c) Write reaction showing reducing property of SO2
(d) Draw a labeled diagram showing ring structure of rhombic sulphur.

Answer 1

Explanation:

The chemical equation to prepare sulphur dioxide from industrial method is

\displaystyle 4FeS_2(s) + 11O_2(g) \rightarrow 2Fe_2O_3(s) +8SO_2(g)4FeS

b) When SO2 is pass through water, it forms sulphurous acid

SO_2+H_2O rightarrow H_2SO_3SO

c) Reaction showing reducing property of sulphur dioxide is

I_2+SO_2+2H_2O rightarrow 2HI+H_2SO_4I

d) A labeled diagram showing ring structure of rhombic sulphur is as shown.

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Answer 2

Answer:

A labeled diagram showing ring structure of rhombic sulphur is as shown.

Explanation:

Step 1:a) The chemical equation to prepare sulphur dioxide from industrial method is

$4 \mathrm{FeS}_2(\mathrm{~s})+11 \mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{Fe}_2 \mathrm{O}_3(\mathrm{~s})+8 \mathrm{SO}_2(\mathrm{~g})$

b) When $\mathrm{SO}_2$ is pass through water, it forms sulphurous acid

$\mathrm{SO}_2+\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{H}_2 \mathrm{SO}_3$

c) Reaction showing reducing property of sulphur dioxide is

$\mathrm{I}_2+\mathrm{SO}_2+2 \mathrm{H}_2 \mathrm{O} \rightarrow 2 \mathrm{HI}+\mathrm{H}_2 \mathrm{SO}_4$

Step 2: d) A labeled diagram showing ring structure of rhombic sulphur is as shown.

In a lab, metallic sulphite or a metallic bisulphite reacts with diluted acid to produce sulphur dioxide. For instance, sodium sulphite and diluted sulfuric acid will react to produce SO2 as a byproduct.

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